The answer is the third one need any more help let me know
Answer : <em>Equation of line is</em> y=Equation of line is y=
x+
Step-by-step explanation:
Theory :
Equation of line is given as y = mx + c.
Where, m is slope and c is y intercepted.
Slope of given line : y =
x+1 is m= 
We know that line : y =
x+1 is parallel to equation of target line.
therefore, slope of target line will be
.
we write equation of target line as y=
x+c
Now, It is given that target line passes through point ( -5,-2)
hence, point ( -5,-2) satisfy the target line's equation.
we get,
y=
x+c
-2=
-5+ c
-5=
+c
c= 
thus, Equation of line is y=Equation of line is y=
x+
OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
Answer:
slope = -2
Step-by-step explanation:
rise/run: y2-y1/x2-x1 .
=12-18/4-1 = -6/3 = -2