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Zielflug [23.3K]
3 years ago
13

HELP PLEASE

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

I chose a box of cereal-------> rectangular prism

Part 1)List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.).

Length: 20 cm

Width: 8 cm

Height: 32 cm

Part 2).

 Describe the shape of the cross-section when the box is cut parallel to the base

the shape of the cross-section would be a rectangle of dimensions

20 cm x 8 cm

Part 3)

What is the surface area of the box? 

surface area=2*area of the base+perimeter of the base*height

area of the base=20*8=160 cm²

perimeter of the base=2*[20+8]-----> 56 cm

height=32 cm

surface area=2*160+56*32------> 2,112 cm²

the answer part 3) is

2,112 cm²

Part 4)

What is the surface area of the box if it is scaled up by a factor of 10?

we know that

surface area of the larger box=[scale factor]²*surface area original box

scale factor=10

surface area original box=2,112 cm²

so

surface area of the larger box=10²*2,112-----> 211,200 cm²

the answer part 4) is

211,200 cm²

Part 5) 

What is the volume of the box?

volume of the box=L*W*H-----> 20*8*32------> 5,120 cm³

the answer Part 5) is

5,120 cm³

Part 6) 

What is the volume of the box if it is scaled down by a factor of 1/10

we know that

the volume of the smaller box=[scale factor]³*volume original box

scale factor=1/10

volume original box=5,120 cm³

so

volume of the smaller box=[1/10]³*5,120-----> 5.12 cm³

the answer part 6) is

5.12 cm³

The length is⇒ 6 in., the width is⇒ 2 in., and the height is⇒ 16 in.

please mark brainliest!

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3 years ago
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Answer:

a

    n=  75, 582

b

  n=    2300

c

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Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

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   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

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Plz help me well mark brainliest if correct!....
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Answer:

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