All categories

3 years ago

If you answer both ill give brainliest.

Mathematics

2 answers:

Ulleksa [173]3 years ago

5 0

B) 13;46

c.19.26

Hope this helps!

Lady bird [3.3K]3 years ago

3 0

Answer:

B) 13;46

c.19.26

this dude is correct just got 100%%%%%

Step-by-step explanation:

You might be interested in

The The point (2,6) is on the line given by which equation below?

maria [59]

Answer:

A y = 3x

Step-by-step explanation:

We can check each line to see if the point is on it

A y = 3x 6 = 2*3 6=6 this is true so the point is one the line

B y = 4-x 6 = 2-4 6 = -2 false

C y = -3x 6 = -3(2) 6=-6 false

D y =-x+4 6 = -2+4 6 = 2 false

3 0

3 years ago

You are given a line that has a slope of 4 and passed through the point (3/8, 1/2). Which statements about the question of the l

alexgriva [62]

Answer:

Statement 1, 2 and 4 are true where as statement 3 is not true.

Step-by-step explanation:

Statement 1: The y-intercept is -1

Point (3/8, 1/2)

Slope = m = 4

y = mx + c

1/2 = 4(3/8) + c

1/2 = 3/2 + c

1/2 = 3/2 + 2c/2

-2 = 2c

c = -1

This statement is true as the y-intercept is -1.

Statement 2: The slope intercept equation is y= 4x - 1

slope = m = 4

y-intercept = c = -1

y = mx + c

y = 4x - 1

This statement is true as the slope intercept equation is y= 4x -1

Statement 3: The point slope equation is y - 3/8 = 4 (x - 1/2)

Point slope equation: y - y1 = m (x - x1)

Points: (x, y) (3/8, 1/2)

y1 = 1/2

x1 = 3/8

Slope = m = 4

y - 1/2 = 4 (x - 3/8)

This statement is not true as the slope intercept equation is y - 1/2 = 4 (x - 3/8) instead of y - 3/8 = 4 (x - 1/2).

Statement 4: The point (3/8, 1/2) corresponds to (x1, y1) in the point slope form of the equation

This statement is true as shown in statement 3's explanation where x1 = 3/8 and y1 = 1/2

6 0

3 years ago

Solve for y. y + 1.05 = 7.26 y = -6.21 y = -8.31 y = 6.21 y = 8.31

Naddik [55]

Y=6.21
hdjsakkaksk
hejsksksjsk

3 0

3 years ago

93% of what number is 25?

marta [7]

Answer: The answer is 327

Explanation: 93×100/25 = 327

6 0

3 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

3 years ago

Read 2 more answers