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Elden [556K]
2 years ago
11

How much water must be added to 30 ounces of a 46% solution of argyrol to reduce it to a solution that is 15% argyrol?

Mathematics
1 answer:
Whitepunk [10]2 years ago
5 0

Answer:

62 oz

Step-by-step explanation:

Let the volume of water to add be x so that the new volume will be (30+x) oz

The new concentration is now 15%, expressed in decimal as 0.15 and it is found by dividing the initial concentration by new volume

\frac {0.46*30}{30+x}=0.15\\\frac {0.46*30}{0.15}=30+x\\92=30+x\\x=62

The volume of water to add is equal to 62 oz

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3(t−2)=−1 What value of t t makes the following equation true?
pashok25 [27]

Answer:

t=5/3

Step-by-step explanation:

in order to get our answer, we have to first open it up which comes to 3t-6=-1

next,we have to isolate the variable, so we add (6) to (-1)

then we get 3t=5

so, t=5/3

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3 years ago
Simplify the product using the distributive property. (-4h +2)(3h +7)
Alekssandra [29.7K]

Answer:

  A.  -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

  = (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

  = -12h² -28h +6h +14

  = -12h² -22h +14 . . . . . . . . collect terms

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3 years ago
A square is cut in half and the diagonal creating two equal triangles of each triangle has an area of 4.5 in.² what is the lengt
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2 years ago
In a fifth-grade class, 3/4 of the students like to go to the movies. Of the students who like to go to the movies, 2/3 of them
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3 years ago
Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a s
Lilit [14]

Answer:

y-2=\displaystyle -\frac{3}{4}(x-1)

OR

y=\displaystyle -\frac{3}{4}x+\frac{11}{4}

Step-by-step explanation:

Hi there!

Point-slope form: y-y_1=m(x-x_1) where <em>m</em> is the slope of the line and (x_1,y_1) is a given point

Given that the slope is -3/4, we can plug it into y-y_1=m(x-x_1) as <em>m</em>:

y-y_1=\displaystyle -\frac{3}{4}(x-x_1)

We can also plug in the given point (1,2):

y-2=\displaystyle -\frac{3}{4}(x-1)

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate <em>y</em>:

y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}

I hope this helps!

8 0
2 years ago
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