a) For there to be a y-intercept of 3, when x=0, y=3.
- A. y=(0+1)(0-3)=-3
- B. y=0²-9=-9
- C. y=3(0)(0-3)=0
- D. y=(0+1)(0+3)=3.
So, the answer is D
b) For there to be roots of 0 and 3, there has to be factors of x and (x-3).
- The only choice that satisfies this is C
Answer:
Because it is a mixed fraction and it should be renamed in order to solve your problem, for the other one CAN NOT be converted into a mixed fraction.
Answer:
= -1/2
Step-by-step explanation:
Pick two points
(1,0) and (3,-1)
Then use the slope formula
m = (y2-y1)/(x2-x1)
= (-1 -0)/(3-1)
= -1 /2
=
<h3>How to solve an expression?</h3>
Therefore,
125 = 5³
27 = 3³
Hence,
Hence,
Both cube root are the same now,
Therefore, we have to add them together.
learn more on expression here; brainly.com/question/19221566
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Answer:
your question itself seems incompete
for absolute value, x can be anything because it will always be positive
Step-by-step explanation: