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gogolik [260]
3 years ago
5

2. If your gross biweekly salary is $3,290, then how much is your annual salary? I

Mathematics
2 answers:
rewona [7]3 years ago
8 0

Answer:

$78,960 is your annual salary

Step-by-step explanation:

By saying biweekly, if you mean that your gross salary for every two weeks is $3,290, then your annual salary will be roughly about $78,960

There are about 4 weeks in a month and you're getting your gross salary biweekly. So $3,290 times 2 equals $6,580. This is your monthly gross salary.

Now, multiply $6,580 times 12 to find out your annual salary because there are 12 months in a year. $6,580 times 12 equals $78,960. This is your annual salary

Hope this helps

aksik [14]3 years ago
6 0

Answer:

Annual Salary = $85,540

Step-by-step explanation:

There are 52 weeks in a year.

If bi weekly salary is $3290

Then you get paid 26 times.

Therefore annual salary = 26 × 3290 =$85,540

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vekshin1

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63

Step-by-step explanation:

Just subtract 26 from 89.

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a = 35°

Step-by-step explanation:

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3 years ago
13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Sholpan [36]

Answer:  Yes, the given set of vectors is a basis of R³.

Step-by-step explanation:  We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :

B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .

For a set to be a basis of R³, the following two conditions must be fulfilled :

(i) The set should contain three vectors, equal to the dimension of R³

and

(ii) the three vectors must be linearly independent.

The first condition is already fulfilled since we have three vectors in set B.

Now, to check the independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the vectors are linearly independent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.

Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.

Thus, the given set is a basis of R³.

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Simplify the given equation 5x+2(x-3)=-2(x-1)
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Answer:

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