A is poor
B is good
C is marginal
Answer:
v See below. v
Step-by-step explanation:
LM = MN
11x - 21 = 8x + 15

x = 12
LM = 11(12) - 21 = 132 - 21 = 111
MN = 8(12) + 15 = 96 + 15 = 111
LN = 111 + 111 = 222
Answer: 1957
Step-by-step explanation:
184 x 7 = 1288
7 x 6 = 42
so you have 42 <span>defective bulbs</span>
Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55
Hope this helped :)