《ANSWER》
《LINEAR EQUATIONS》
Solving all we get as
↪1) 5 (x -2) = 5x - 7
since after solving X is cancelled , NO SOLUTION
↪2) -3 (x - 4) = -3x + 12
SINCE after solving X is any value , infinitely many solutions
↪3) 4 (x + 1) = 3x + 4
solving we get as , 4x+ 4 = 3x + 4 =》 X =0
only one solution
↪4) -2 (x-3) = 2x - 6
Only one solution
↪5) 6 (x + 5) = 6x + 11
NO SOLUTION
All the equations are solved by the distributive law of algebra
1: (-1,-1) is (x, y) to see if it is a solution, you would just plug in x and y and see if the equation is true.
-4 (-1) + 2(-1) = 2
4 + -2 = 2
2 = 2 CORRECT
So... plug in x and y in the second equation to Make sure it works for that one too.
-1 + -1 = -2
-2 = -2 CORRECT
So, yes. (-1,-1) is a solution to both equations.
The given number is not a solution of the equation i.e. the number is an inequality
<h3>How to determine the solution?</h3>
The equation is given as:
3x- 4 = 10
The number is given as:
5
This means that
x = 5
Substitute x = 5 in 3x- 4 = 10
3 * 5- 4 = 10
Evaluate the product
15- 4 = 10
Evaluate the difference
11 = 10
The above equation is not true i.e. the equation is actually an inequality
Hence, the given number is not a solution of the equation i.e. the number is an inequality
Read more about inequality at
brainly.com/question/24372553
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