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3 years ago

A restaurant bill came to $60. If 15% of this bill was left as a tip, how much was the tip

Mathematics

2 answers:

Brrunno [24]3 years ago

6 0

Answer:

Step-by-step explanation:

10% of 60 = 6

so 5% = 3

15% = 9

garik1379 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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Does anyone know matrices?

Sunny_sXe [5.5K]

Answer:

this is Geometry right?

Step-by-step explanation:

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Read 2 more answers

The probability that event M will not occur is 0.8 and the probability that event R will not occur is 0.6. If events M and R can

ololo11 [35]

Answer:

11/25 The right answer is not a part of the options given.

Step-by-step explanation:

Given;

Probability that event M will not occur = 0.8

Probability that event R will not occur = 0.6

Then the ;

Probability that event M will occur = 1 - 0.8 = 0.2

Probability that event R will occur = 1 - 0.6 = 0.4

If events M and R cannot both occur, probability that either event M or event R will occur

= probability that M occurs and R does not or the probability that R occurs and M does not

= 0.2 × 0.6 + 0.4 × 0.8

= 0.12 + 0.32

= 0.44

= 11/25

6 0

4 years ago

Tion 15/30

vitfil [10]

The percentage of students that passed the exam is 25.2%

The given parameters;

number of the males, = 85

number of the females, = 30

percentage of the female that passed = 40%

percentage of the male that passed, = 20%

To find:

the percentage of students that passed the exam

The number of the male students that pass the exam;

$= 0.2 \times 85 \\\\= 17$

The number of the female students that pass the exam;

$= 0.4 \times 30 \\\\= 12$

The total number of students in the school;

= 85 + 30

= 115

The total number of the students that passed the exam;

= 17 + 12

= 29

The percentage of students that passed the exam;

$= \frac{total \ number \ that \ passed }{total \ number \ of \ the \ students} \times 100\% \\\\= \frac{29}{115} \times 100\%\\\\= 25.2 \%$

Thus, the percentage of students that passed the exam is 25.2%

Learn more here: brainly.com/question/1163846

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3 years ago

Is knowing two sides and another angle enough to say they are congruent?

olga55 [171]

If there is more information then you should use it but if that is then yes it is possible if you think hard enough.

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3 years ago