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sleet_krkn [62]
4 years ago
8

Tony rounded each of the numbers 1, 143 and 1, 149 to the nearest hundred which word correctly compares the rounding numbers

Mathematics
1 answer:
Montano1993 [528]4 years ago
4 0

Full Question:

<em>Tony rounded each of the numbers 1,143 and 1,149 to the nearest hundred. Which choice correctly compares the rounded numbers? </em>

<em></em>1,000 = 1,000

1,140< 1,150

1,100 = 1.100

1,140>1,150

Answer:

1,100 = 1,100

Step-by-step explanation:

Given

1,143 and 1,149

Required

Which of the option is correct

We start by approximating both numbers to nearest digit

<em>1,143; when approximated to nearest hundred is 1,100</em>

<em>1,149; when approximated to nearest hundred is also 1,100</em>

Hence;

1,143 ≅ 1,100

1,149 ≅ 1,100

Comparing both results, we have that

1,100 = 1,100

From the list of given options, option C is correct;

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Prove whether the quadrilateral is a parallelogram using the Distance &amp; Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -
amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80

E(5, 2), F(4, -4)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

F(4, -4), G(-6, -12)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80

G(-6, -12),  D(-5, -6)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

8 0
3 years ago
hadley earned $27 for a fundraiser. thea earned $81 for the fundraiser. How much more money did thea earn than Hadley? a. 2.5 b.
Ksenya-84 [330]

To find the difference, subtract Thea's earnings from Hadley's earnings.

81-27=54

Thea earned $54 more than Hadley.

8 0
4 years ago
Read 2 more answers
Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1
Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

8 0
3 years ago
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Neporo4naja [7]

Answer:

No solution

Step-by-step explanation:

Solving inequalities is similar to solving equations. First let's distribute the 3 with (k-9)

3(k - 9) > 3k + 6

3k - 27 > 3k + 6

(Subtract 3k from both sides)

- 27 > 6

- 33 > 0

(Subtract 6 from both sides. You can also add 27 to both sides. You will get the same answer.)

This inequality is invalid. There are no values of k that make the inequality true.

4 0
3 years ago
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lutik1710 [3]

Answer:

1. 2(a^2 + 3a + 9)

2. 5(x^2 - 1)

3. 3(t + 8)(t - 2)

4. n(4 - n)

Step-by-step explanation:

For 1, you can only factor out the constant from each.

For 2, you can also only factor out the constant, but remember that you include the 1 when dividing 5 by 5.

For 3, you can factor out the constant and the variables.

For 4, you can only factor out the variable.

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2 years ago
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