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Olenka [21]
3 years ago
8

Please help, I can’t do this

Mathematics
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

I believe your answer is C

Step-by-step explanation:

m messages times 5 hours = 5m

p messages times 4 hours = 4p

You want total, so 5m + 4p

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What is an algebraic expression for 'two thirds of a number (d) to the third power' ?
horrorfan [7]
It is (2/3d)^3
Make sure the exponent is on the outside. This is because you are raising 2/3d. Not just D

5 0
3 years ago
Read 2 more answers
Hello can you please help me posted picture of question
loris [4]
The sample space will be: {1, 2, 3, 4, 5, 6}

Event A is: {Rolling 1,2 or 3}

Complement of event A will contain all those outcomes in the sample space which are not a part of event A.

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Thus option A gives the correct answer
3 0
3 years ago
I need to know the answer
Elan Coil [88]
The mistake is n third line  - adding 3w
96 + 2w =2(80 - 3w)
96 + 2w = 160 - 6w
        + 6w           + 6w
96 + 8w  = 160
 - 96              -96
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w = 8   weeks answer
8 0
3 years ago
Use pi=3<br> Calculate the area of a circle with a diameter of 10cm
GalinKa [24]
Area of a circle is 75 cm².

Area of a circle is computed by multiplying pi to the square of the radius.

A = πr²

diameter = 10 cm
radius = d/2 = 10/2 = 5 cm
pi = 3

A = 3(5cm²)
A = 3(25cm²)
A = 75 cm²
7 0
3 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
3 years ago
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