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-Dominant- [34]
3 years ago
7

I serve a volleyball at a 730 angle with the horizontal, and an initial speed of 5.6 feet per second. What is the component form

of the velocity? Please round to three decimal places out from the zero.
Mathematics
2 answers:
noname [10]3 years ago
4 0
You would split out the velocity into x and y components.
X component: 5.6cos(73)= 1.637i
Y component: 5.6sin(73)= 5.355j

Therefore velocity in its component form is 1.637i + 5.355j ft/s
vredina [299]3 years ago
4 0

Answer:

Velocity = 1.637i + 5.355j

Step-by-step explanation:

If you serve a volleyball at 73° angle with the horizontal and an initial speed of 5.6 feet per second.

Then horizontal component of the velocity = 5.6×cos73°i = 1.637i

and vertical component of the velocity = 5.6×sin73°j = 5.355j

Finally the component form of the velocity will be = 1.637i + 5.355j

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Compare partial products and regrouping
Stella [2.4K]

Let us first describe how partial product and regrouping are alike:

Partial Products and Regrouping are alike because both methods are multiplied by one number and if the product of the number has 2 digits it can be carried.

Now let us discuss how they are different:

Partial Products and Regrouping are different because Partial Products are doing multiplication step by step and regrouping is regular multiplication.

Hope it helps.

5 0
3 years ago
Drag each figure to show if it is similar to the figure shown or why it is not similar. 4in by 6in
Schach [20]

Answer:

9

Step-by-step explanation:

cuz i said

4 0
3 years ago
❤❤❤please help on this
shtirl [24]

Since you answered the first 2 i can go to c and d.

C can really be anything since it's being multiplied by 0 no matter what you put there it will be 0.

But for D it's 1/10^2

Hope this helps ^^

3 0
3 years ago
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
What does this equal please help
Juliette [100K]
It will be 3a+ 4b^2 =50 that’s what I get at least
5 0
3 years ago
Read 2 more answers
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