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liraira [26]
4 years ago
13

X-82.5=134 solve for x

Mathematics
1 answer:
Lilit [14]4 years ago
3 0

Answer:

X=216.5

Step-by-step explanation:

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The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
What two formulas are necessary to find the area of a segment of a circle?
tresset_1 [31]

Answer:

They are: area of sector and area of triangle

Step-by-step explanation:

Area of segment=area of sector - area of triangle

So we need both the area of sector and area of triangle to calculate for the area of a segment

8 0
3 years ago
(x^2–x–4)multiplied by(x–5)
Sergio [31]

(x-5)(x^2-x-4) =x^3-6x^2+x+20

Step-by-step explanation:

Given polynomials are:

x^2-x-4\\and\\x-5

Both polynomials have to be multiplied. We will use distributive property for the said purpose

So,

(x-5)(x^2-x-4)\\=x(x^2-x-4)-5(x^2-x-4)\\=x^3-x^2-4x-5x^2+5x+20

Combining alike terms

=x^3-x^2-5x^2-4x+5x+20\\=x^3-6x^2+x+20

Hence,

(x-5)(x^2-x-4) =x^3-6x^2+x+20

Keywords: Polynomials, Multiplication

Learn more about polynomials at:

  • brainly.com/question/4703807
  • brainly.com/question/4703820

#LearnwithBrainly

7 0
3 years ago
-6y + 15 = -21<br><br>help me out please​
AleksandrR [38]

Answer:

y=6

Step-by-step explanation:

-6y+15=-21

-6y=-21-15 (it becomes negative on this side.)

-6y=-36 (divide both sides by -6.)

y=6

8 0
3 years ago
Read 2 more answers
Multiply the polynomial x (3x-1)(2x+5) also what is the degree of the polynomial
Readme [11.4K]

Answer:

Result after multiplication of polynomial is: 6x^3+13x^2-5x

Degree of polynomial = 3

Step-by-step explanation:

The given polynomials are:

x(3x-1)(2x+5)

In order to multiply the given polynomials we have to work step by step. First of all the polynomials in the bracket will be multiplied and then their result will be multiplied with x.

So, multiplying the polynomials in round brackets first

=x(3x-1)(2x+5)\\= x\{3x(2x+5)-1(2x+5)\}\\=x\{6x^2+15x-2x-5\}\\=x(6x^2+13x-5)

Now multiplying with x

= 6x^3+13x^2-5x

Degree of a polynomial is the highest exponent of variable in the polynomial.

In the acquired result, the highest exponent of x is 3 so the degree is 3.

Hence,

Result after multiplication of polynomial is: 6x^3+13x^2-5x

Degree of polynomial = 3

3 0
3 years ago
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