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2 years ago

How do you do it .Thank you

Mathematics

1 answer:

GrogVix [38]2 years ago

5 0

An improper fraction is when the numerator is greater. For example, 1 7/8 = 15/8

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PLS HELP ME ASAP!!!!

mafiozo [28]

Answer:

20 Km per hour.

6 0

3 years ago

Help me please someone.

Free_Kalibri [48]

Answer:

divide by 4 from each side

Step-by-step explanation:

$\frac{x}{4} > 13$

÷4 ÷4

x>13÷4

5 0

2 years ago

Read 2 more answers

Which is the simplified form of the expression?

Anon25 [30]

Given:

Consider the given expression is:

$10n-\dfrac{1}{3}(9n-12)$

To find:

The simplified form of the given expression.

Solution:

We have,

$10n-\dfrac{1}{3}(9n-12)$

Using distributive property, it can be written as:

$=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)$

$=10n-3n+4$

$=7n+4$

Therefore, the correct option is A.

4 0

3 years ago

Help Me Find The X Please

Papessa [141]

Answer:

x = 16

y = 16 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/hyp

sin 60 = y/ 32

Multiply each side by 32

32 sin 60 = y

32 ( sqrt(3) /2) = y

16 sqrt(2)

cos theta = adj/ hyp

cos 60 = x /32

32 cos 60 = x

32 (1/2) =x

16 =x

4 0

2 years ago

Read 2 more answers

Solve this equation for x: 2x^2 + 12x - 7 = 0

zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: $2x^2 + 12x - 7 = 0$

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

$2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7$

Step 2: Divide the equation all through by the coefficient of $x^2$ which is 2.

$x^2 + 6x=\frac{7}{2}$

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3= $3^2$

Therefore, we have:

$x^2 + 6x+3^2=\frac{7}{2}+3^2$

Step 4: Write the Left Hand side in the form $(x+k)^2$

$(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\$

Step 5: Take the square root of both sides and solve for x

$x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355$

6 0

2 years ago