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kap26 [50]
2 years ago
9

Somebody help me im stuck!! I suck at geometry

Mathematics
1 answer:
marta [7]2 years ago
4 0
The  answer  would be  c 8

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Please help me out i will reward brainliest
Nadusha1986 [10]
I can not see the picture so i caN NOT HELP SORRY

5 0
3 years ago
Monique has 2 less than half as many pairs of shoes as Dalia . Monique has four pairs of shoes. Which equation can be used to fi
viktelen [127]

Answer:

4m +2m = D

Step-by-step explanation:

i think i havent done this in a long time but idk

ik that dalia has 6 shoes

4 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
3 years ago
Please help ASAP 25 pts + brainliest to right/best answer
Whitepunk [10]
The answer seems to be D!!
4 0
3 years ago
Read 2 more answers
Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
denis23 [38]
Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

P(a\ \textless \  X\ \textless \  b)=P\left(z\ \textless \  \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \  \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\  \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \  \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \  \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\  \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344</span>
6 0
3 years ago
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