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3 years ago

Parallelogram ABCD has the angle measures shown. Can you conclude that it is a rhombus, a rectangle, or a square? Explain.

Mathematics

1 answer:

Hoochie [10]3 years ago

5 0

Answer:

The correct option is parallelogram ABCD is a rhombus, because the diagonal bisects two angles

Step-by-step explanation:

In triangle ABD:

∠B = ∠D

Thus AB=AC by the property of opposite sides of equal angles are equal

In triangle CBD

∠B = ∠D

Thus CB=CD by the property of opposite sides of equal angles are equal

Thus all four sides of quadrilateral ABCD are equal

And diagonal BD bisects the angles

So, it is a rhombus

Therefore the correct option is parallelogram ABCD is a rhombus, because the diagonal bisects two angles....

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A car manufacturer announced that next year the price of a certain model car would increase by 5.5 %. This year the price is $1

zloy xaker [14]

Answer:

Increase: $969.93 New Price: $18,604

Step-by-step explanation:

I got this answer by finding out how much of the initial price 5.5% was, it ended being 969.925 so I rounded that to 969.23 so that I may found how much the price increased, then I added the increase price to the initial price so that I may find out how much the car would cost next year which is, $18,604.

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3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height

Ilia_Sergeevich [38]

Answer:

$\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s$

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

$\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}$

From this point on, you have two possibilities, either you find each individual $y_{f}, y_{0}, t_{f}, t_{0}$ and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

$t_{f}-t_{0}=\Delta t$

and we also know that:

$t_{f}=t_{0}+\Delta t$

in order to find the final position, we can substitute this final time into the function, so we get:

$y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}$

so we can rewrite our formula as:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}$

$y_{0}$ will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

$y_{0}=29t-22t^{2}$

$y_{0}=29(1)-22(1)^{2}$

$y_{0}=7ft$

we can substitute it into our average velocity equation:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}$

and we also know that the initil time will always be 1, so we can substitute it as well.

$\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}$

so we can now simplify our formula by expanding the numerator:

$\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}$

$\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}$

we can now simplify this to:

$\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}$

Now we can factor Δt to get:

$\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}$

and simplify

$\overline{v}=-15-22\Delta t$

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

$\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s$

$\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s$

$\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s$

$\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s$

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3 years ago

5. Three sides of a triangle have sides of length 6 inches, 8 inches, and 10 inches. One

IrinaVladis [17]

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3 years ago

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jekas [21]

Answer:

15.18

Step-by-step explanation:

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3 years ago

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Pls help with math ASAP

Natasha_Volkova [10]

125.6

Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
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3 years ago