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Anni [7]
3 years ago
8

Identify whether the given pairs of events in a roulette game are mutually exclusive. Drag the items on the left to the correct

location on the right.
mutually exclusive events

1 to 12 and red

not mutually exclusive

events

1 to 12 and 25 to 36

1 to 18 and odd

black and red

even and black
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:

Correct

not mutually exclusive events 1 to 12 and red

Correct

mutually exclusive events 1 to 12 and 25 to 36

Correct

not mutually exclusive events 1 to 18 and odd

Correct

mutually exclusive events black and red

Correct

not mutually exclusive events even and black

Step-by-step explanation:

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Mario has a remaining balance of $1,300 on his credit card his credit card has an APR of 20% how much will he pay in interest in
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The correct answer for this problem is 6,500 in one month
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3 years ago
These are the first sentences in the short story, “the gift of magi” by O. Henry: “one dollar ad eighty/seven cents. That was al
saveliy_v [14]
1 quarter = 25 cents
1 dime = 10 cents
1 nickel = 5 cents
1 penny = 1 cent

1) You need 2 pennies.
2) You need 7 pennies.
3) You need 9 dimes.
4) You need 2 quarters and 0 nickels.
5) You need 5 nickels.

Hope this helps =)
4 0
3 years ago
Read 2 more answers
When would you want to use the median over the mean for describing the measure of center for a data set?
zheka24 [161]
Hello!

Sometimes when there are outliers in a data set, for example 1, 20,25,26,30, one is the outlier and when you find the mean it will not represent the data in the most accurate way. This is when you use the median to represent the part of the data set that has the information that is close together.

I hope this helps!
8 0
3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
F(x) = 4x + 7, g(x) = 3x2
Luda [366]

Answer:

(1)

(f+g)(x)=3x^2+4x+7

(2)


Step-by-step explanation:

we are given

f(x)=4x+7

g(x)=3x^2

we have to find (f+g)(x)

we can write

(f+g)(x)=f(x)+g(x)

now, we can plug values

and we get

(f+g)(x)=4x+7+3x^2

we can also write as

(f+g)(x)=3x^2+4x+7

so, answer is

(f+g)(x)=3x^2+4x+7

7 0
3 years ago
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