Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M± where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12± =12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
56
Step-by-step explanation:
First you want to multiply -7 and -8. after you do that you'll get your answer of 56 and you can check your answer by doing 56/-7 which equals -8.
Answer:
34
Step-by-step explanation:
It can't be higher than 34 since 174÷5= 34.8