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Setler [38]
3 years ago
6

What is the volume of this square pyramid? 1296 cm^3 1620cm^3 3888cm^3 11,664cm^4

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

\bf \textit{volum of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{18\times 18}{324}\\ h=12 \end{cases}\implies V=\cfrac{1}{3}(324)(12)\implies V=1296

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Find the mean of the data in the dot plot below. Make sure to show your work and explain the steps you took in solving the probl
zaharov [31]

Answer: 6.

Step-by-step explanation: To find the mean, the first step is to add all the data together.  Here's how it should look:

2 + 3 + 6 + 6 + 7 + 8 + 8 + 8 = 48.

Next, you need to divide whatever you get after adding the data by how many numbers there are for your data.  In this case, 48 was the answer when we added all the data.  In total, you have 8 numbers in your data, so you need to divide 8 from 48.  It should look like this:

48 / 8 = 6.

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IRINA_888 [86]

Answer:

0.0864 < p< 0.1358

We are confident (95%) that the true proportion of people admitted they did not buy a ticket is betwen 0.0864 and 0.1358.  

Step-by-step explanation:

1) Data given and notation  

n=621 represent the random sample taken    

X=69 represent the people admitted they did not buy a ticket

\hat p=\frac{69}{621}=0.111 estimated proportion of people admitted they did not buy a ticket

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic

p= population proportion of people admitted they did not buy a ticket

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

2) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.111 - 1.96 \sqrt{\frac{0.111(1-0.111)}{621}}=0.0864

0.111 + 1.96 \sqrt{\frac{0.111(1-0.111)}{621}}=0.1358

And the 95% confidence interval would be given (0.0864;0.1358).

0.0864 < p< 0.1358

We are confident (95%) that the true proportion of people admitted they did not buy a ticket is betwen 0.0864 and 0.1358.  

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3 years ago
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Answer:

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