3 years ago

What is the value of x? Enter your answer in the box.

Mathematics

1 answer:

natka813 [3]3 years ago

3 0

As you see half of X is 68 as shown on the top wouldn't you do 68*68?

You might be interested in

Which ordered pair could you remove from the relation {(-1,0), (1,3), (2,2), (2,3), (3,1)} so that it becomes a function?

Scrat [10]

I think the answer is (2,3)

6 0

3 years ago

A farmer has a bale of hay with mass of 36 kilograms. How many milligrams of hay are in the bale?

Ilia_Sergeevich [38]

KILO=1000.............. MILLI= thousandth

1kg is 1000 grams

1 milligram is one thousandth of a gram, so a 1 gram = 1000mg.

in 36 kg, then there are 36 * 1000 grams.

and in (36*1000) grams there are (36*1000)*1000 mg, 36,000,000 mg.

4 0

3 years ago

Jaden sells a painting for 10 times the original price he sells a painting for $45.50 what was the original price of this painti

Ymorist [56]

$x-\ original\ price\\\\
10x=45,50\ \ \ \ | divide\ by\ 10\\\\
x=4,550\$\\\\
Original\ price\ is\ 4,550\$.$

6 0

3 years ago

Read 2 more answers

2. What is the value of 6x – 3y if x = 5 and y = 1

vesna_86 [32]

Step-by-step explanation:

x=5,y=-1

6(5)-3(-1)=30+3=33

answer G .33

4 0

3 years ago

Do you agree with the researchers method of predicting the population? Why or why not?

Burka [1]

Yes, I agree with the researcher's method. All the values of $a_{n}$ in the table correspond to the values of n by using their formula.

Step-by-step explanation:

Step 1:

If we substitute the values of n in the researcher's equation and we get the right values of $a_{n}$ , we can agree with the researcher's method.

The researcher's formula is $a_{n} = 1000(2)^{n-1}.$ Here $a_{n}$ is the wombat population and n is the number of years.

Step 2:

When n = 1, $a_{1} = 1000(2)^{1-1} = 1000(1) = 1,000,$

when n = 2, $a_{2} = 1000(2)^{2-1} = 1000(2) = 2,000,$

when n = 3, $a_{3} = 1000(2)^{3-1} = 1000(4) = 4,000,$

when n = 4, $a_{4} = 1000(2)^{4-1} = 1000(8) = 8,000,$

when n = 5, $a_{5} = 1000(2)^{5-1} = 1000(16) = 16,000.$

As all the values correspond to the values on the table, I agree with the researcher's method.

6 0

3 years ago