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Vika [28.1K]
4 years ago
13

Plzzzzz help URGENT!!! will fail!!!! Need answer ASAP!!!!!!!

Mathematics
1 answer:
Lyrx [107]4 years ago
6 0

Answer: 27.73 (SORRY IF THIS IS WRONG)

Step-by-step explanation:

- First, we need to find the area of the circle. (Pie x r^2)

- That will result in 28.27. Now that we have the area of the circle, now we need to find the rectangle.

- If the dimensions for the rectangle are 8 and 7, the area is 56.

- Find the difference between the area's. (56 - 28.27)

- The shaded region's area is 27.73.

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Can someone please help me with question 6
olasank [31]

Answer:

5323

Step-by-step explanation:

453

7 0
3 years ago
What is the equation of a circle with the center(-9,-5) and radius equals 9
mezya [45]

Answer:

(x+9)^2+(y+5)^2=81

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2

(h,k)=center

r=radius

so if you just insert the center (-9,-5) and the r with 9

(x-(-9))^2+(y-(-5))^2=9^2

(x+9)^2+(y+5)^2=81

Hope that helps :)

6 0
3 years ago
Read 2 more answers
Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

6 0
1 year ago
370 is 125% of what number?
bonufazy [111]

Answer:

125/100 x N = 370

x 100 x 100

125n = 37,000 (since your multiplying what you got to the variable)

Divide by 125

N = 296

7 0
3 years ago
Help please n thanks
garri49 [273]

Answer:

The answer I would choose is c

Hope this helped :)

5 0
3 years ago
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