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enot [183]
3 years ago
8

Pls guys help me with this i will give u more points!

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

3x - 4y =  - 6 \\  - 2x + y = 1

<em>The Ordered pair of solution will be (x,y)=(2,3)</em>

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3>Steps below⤵️</h3>

  • Solve the second equation for y
  • Substitute the given value of y into the first equation
  • Solve the first equation for x
  • Substitute the given value of x into the second equation
  • Solve the equation for y
  • The possible solution of the system is the ordered pair (x,y)
  • And we are done solving!!~

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a new statue with a circular base is being unveiled in a downtown park. the statue base has a radius of 8 feet. round your answe
fiasKO [112]
I believe you are asking for the area of the statue base.

r^2x3.14 = area of a circle

8 x 8 = 64

64 x 3.14 = 200.96
200.96 rounded = 201

The area of the statue base is 201 square feet.
5 0
3 years ago
Which is an example of categorical data?
Ostrovityanka [42]

Answer:

B

Step-by-step explanation:

I'm positive its B, if it's not B then then D

hope this helps!

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3 years ago
A basket contains eight pieces of fruit: three apples three oranges and two bananas. Jonah takes a piece of fruit at random from
oksian1 [2.3K]
The answer is 3/8 because there is 3 oranges out of eight fruit.
8 0
4 years ago
Find f. f ″(x) = x^−2, x &gt; 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
I need help plz anyone ​
Contact [7]

Answer:

e

Step-by-step explanation:

7 0
3 years ago
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