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3 years ago

Find the value of 14x3+12 divide 4

Mathematics

2 answers:

Llana [10]3 years ago

8 0

The answer is 13.5<<<<<<<<<<<<<<<<

pochemuha3 years ago

5 0

The answer is 11.25!

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3( 3v +5 ) = 39<br> Solve this problem

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Step-by-step explanation:

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2 years ago

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Find the least common multiple of 20, 4, and 5

Salsk061 [2.6K]

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3 years ago

Round to the nearest hundredth 26.9816

VARVARA [1.3K]

$\huge{\boxed{26.98}}$

The hundredths place is the second place after the decimal point. In this case, it is $8$ .

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3 years ago

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Evgen [1.6K]

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3 years ago

If a cup of coffee has temperature 97Â°C in a room where the ambient air temperature is 25Â°C, then, according to Newton's Law o

FinnZ [79.3K]

Answer:

The average temperature is $T_{a} = 81.95^oC$

Step-by-step explanation:

From the question we are told that

The temperature of the coffee after time t is $T(t) = 25 + 72 e^{[-\frac{t}{45} ]}$

Now the average temperature during the first 22 minutes i.e fro $0 \to 22$ minutes is mathematically evaluated as

$T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx$

$T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.$

$T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.$

$T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]$

$T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]$

$T_{a} = 81.95^oC$

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3 years ago