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Whitepunk [10]
2 years ago
5

If Y co-ordinate of a point is zero then this point always lies​

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer:

on the x-axis

Step-by-step explanation:

(assuming the point is on a rectangular coordinate plane) The y-coordinate determines where a point is "vertically". The x-axis is equal to y=0, so if the y-coordinate of a point is 0, i.e. (x,0), the point always lies on the x-axis.

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If T(n) = 2n - 7 what is the 5th term
nadezda [96]
Plug in n = 5 to find the 5th term

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2. Evaluate f(3) for f(x) = 2x - 9
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Nat2105 [25]

Answer:

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What is the equation of the line that passes through the points (-3,5) (6,8)
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(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
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