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Setler [38]
3 years ago
14

BRAINLIEST!!!

Mathematics
2 answers:
marshall27 [118]3 years ago
5 0
5 cats 1 bag of food so twenty cats would be 4 bags of food per month
 5c = 1b   5 x 4 = 20  20c = 4b
c = cats 
b = bags of food
kifflom [539]3 years ago
4 0
20 cats * ( 1 bag of food / 5 cats per month ) = 4 bags of food per month to feed all 20 cats

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Alisiya [41]
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3 0
2 years ago
What is the ratio for 8 and 12
Vitek1552 [10]
It can be 8:12 or as a fraction it’s 8/12
5 0
3 years ago
The Software Company earned 2,247,852,199 dollars last year. This year they earned 3,000,962,245 dollars. Which is the best esti
RSB [31]

You know the following information:

1. The amount of money (in dollars) earned last year was:

2,247,852,199

2. The amount of money (in dollars) earned this year, is:

3,000,962,245

Then, to estimate the sum (the total amount of money the Software Company earned in those two years, you can round the numbers to the nearest billion.

Having:

2,247,852,199

You need to look at the digit located in the Hundred millions place. Notice that this is:

2

Then, since:

2

You need can't round up. Then:

2,247,852,199\approx2,000,000,000

Now, having:

3,000,962,245

You can identify that the digit in the Hundred millions place is

0

Therefore:

3,000,962,245\approx3,000,000,000

Now you can add the numbers rounded:

2,000,000,000+3,000,000,000=5,000,000,000

Hence, the answer is: Option B.

5 0
1 year ago
2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for
kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The variables are listed as follows:

  • \pi is the sample proportion, which is also the estimate of the parameter.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.90}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

n = 150, \pi = \frac{15}{150} = 0.1

The margin of error is of:

M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%

The interval is given by the estimate plus/minus the margin of error, hence:

  • The lower bound is: 10 - 2.45 = 7.55%.
  • The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}

\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}

(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

3 0
1 year ago
Double somme help please
Lady_Fox [76]

Answer:

looks like a nazi symbol

Step-by-step explanation:

7 0
2 years ago
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