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nevsk [136]
3 years ago
8

3x = 2x + 18 : slove the equation

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0

Answer:

18

Step-by-step explanation:

3x = 2x + 18

3x - 2x = 18

x = 18

Romashka [77]3 years ago
3 0

Answer:

3x= 2x+18

3x-2×=2×-2×+18

×=18

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Given the function h(x)=x^2-7x+6h(x)=x
Goryan [66]

Answer:

0 (no change)

Step-by-step explanation:

Recall that the average rate of change of a function f(x) over the interval [a,b] is equal to \frac{f(b)-f(a)}{b-a}:

\frac{h(b)-h(a)}{b-a}\\ \\\frac{h(6)-h(1)}{6-1}\\\\\frac{0-0}{5}\\ \\0

Hence, the average rate of change of the function h(x) over the interval [1,6] is 0, or no change.

3 0
2 years ago
The organizers of a walkathon get cost estimates from two printing companies to print brochures to advertise the event. The cost
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3 years ago
Two containers hold several balls. Once a second, one of the balls is chosen at random and switched to the other container. Afte
natka813 [3]

Answer:

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(b) 4 balls

Step-by-step explanation:

Let

N \to Number of balls

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For 2 boxes, it is:

Pr = 2 * 0.5^N

From the question, we have:

\frac{80}{10000} \to Favorable outcome

To solve for N, we have:

2 * 0.5^N = \frac{80}{10000}

2 * 0.5^N = 0.008

Divide both sides by 2

0.5^N = 0.004

Take log of both sides

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Apply law of logarithm

N\log(0.5) = \log(0.004)

Make N the subject

N = \frac{\log(0.004)}{\log(0.5)}

N =7.966

Approximate

N = 8

Solving (b): Balls in one of the two boxes.

Here, we assume that each ball will have almost the same number of balls at a given instance;

Hence, we have:

Balls \approx \frac{N}{2}

Balls \approx \frac{8}{2}

Balls \approx 4

<em>4 balls in each box</em>

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3 years ago
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Orlov [11]
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5 0
4 years ago
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