We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56
let the width of the rectangle be x
area of rectangle is l*b
x * (x + 6) = 40^2
x^2 + 6x = 40^2
x^2 + 6x = 1600
x + 6x =√1600
x + 6x = 40
7x = 40
x = 5.7
Hope you found this useful
Answer:
Hi there!
The correct answer is: 20
Step-by-step explanation:
knowing this a right triangle you can solve this problem in two ways
Method One: Pythagorean Theorem
a^2 + b^2 = c^2 then plug in the values
(12)^2 + (16)^2 = c^2 this will come out to be 400 = c^2
square root both sides and you get c = 20
Method Two: Pythagorean Identities
if you ever learned the Pythagorean identity 3,4,5
this triangle is indeed a 3,4,5 triangle it's just that each side is multiplied by the factor 4
so in this case since you know the missing side should be 5 you just multiply 5 by 4 and you get 20
Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: "A rectangular yard is 20 ft by 15 ft. The yard is cover with grass except for 8.5 feet square flower garden. How much grass is in the yard?"</h3><h3 />
The area of a rectangle can be calculated with the following formula:
Where "l" is the lenght of the rectangle and "w" is the width.
Based on the data given in the exercise, you can identify tha the length and the width of the rectangular yard are:
Then, you can substitute these values into the formula and then evaluate in order to find the area of the entire yard:
The area of the flower garden which is an square, can be calculated with this formula:
Where "s" is the side length.
In this case you know that:
Then the area of the flower garden is:
<em> </em>Since this is not covered with grass, you need to subtract both areas calculated above in order to find the surface covered with grass in the yard.
This is:
