Step-by-step explanation:
g(x) = ax²+bx+c
g(x)=−3x²−6x+5
a = -3, b= -6, c = 5
since a <0 , the function has only maximum value.
=> g'(x) = 0
-6x -6 = 0
-6x = 6
x = -1
the maximum value => g(-1) =
-3(-1)²-6(-1)+5 = -3+6+5 = 9
the domain : {x | x € Real numbers}
the range : {y| y ≤ 9, y € Real numbers}
the function is increasing for x < -1
the function is decreasing for x > -1
5 divides by 2 is 2.5 I hope that hekos
(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
What’s angle 1? U need to post a pic
