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lana [24]
2 years ago
7

Hello! Guys I need some you to help me to solve this Areas of triangles homework. Shown down below. can you also give me the equ

ation to solve it aswell.
I also need help on theses trapezium area questions can you give me the equation.
thanks!
( Do Not Delete This Question, Anybody!)**

Mathematics
2 answers:
scoundrel [369]2 years ago
6 0

Answer:

sorry I didn't this answer

UNO [17]2 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

(1)

b = 6 and h = 9 , then

A = \frac{1}{2} × 6 × 9 = 3 × 9 = 27 cm²

(2)

b = 3 and h = 5 , then

A = ×\frac{1}{2} × 3 × 5 = 1.5 × 5 = 7.5 cm²

(3)

b = 6 and h = 10 , then

A = \frac{1}{2} × 6 × 10 = 3 × 10 = 30 cm²

(4)

b = 8 and h = 14 , then

A = \frac{1}{2} × 8 × 14 = 4 × 14 = 56 cm²

(5)

b = 7 and h = 9 , then

A = \frac{1}{2} × 7 × 9 = 3.5 × 9 = 31.5 cm²

--------------------------------------------------------------------

The figures are composed of a rectangle and a triangle

The area is the sum of the areas of the rectangle and the triangle

A = (5 × 4) + \frac{1}{2} × 5 × 4

   = 20 + 10

    = 30 cm²

(2)

A = (7 × 5) + \frac{1}{2} × 7 × 2

   = 35 + 7

    = 42 cm²

--------------------------------------------------------------------

The area (A) of a trapezium is calculated as

A = \frac{1}{2} h (a + b)

where h is the perpendicular height and a, b the parallel bases

(1)

A = \frac{1}{2} × 5 × (7 + 11) = 2.5 × 18 = 45 cm²

(2)

A = \frac{1}{2} × 6 × (6.6 + 8.4) = 3 × 15 = 45 cm²

(3)

A = \frac{1}{2} × 4.3 × (9.1 + 7.1) = 2.15 × 16.2 = 34.83 cm²

------------------------------------------------------------------------

The figure consists of a rectangle in the middle and 2 trapezium at the ends

A = \frac{1}{2} × 6 × (10 + 12) + (12 × 15) + \frac{1}{2} × 11 × (12 + 9)

    = 3 × 22 + 180 + 5.5 × 21

     = 66 + 180 + 115.5

     = 361.5 m²

Divide by 20 to find number of cans required

361.5 ÷ 20 = 18.075

Only whole tins can be bought , so 19 tins required

cost = 19 × £6 = £114

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For each 11 mm of coloured fabric Nick uses to make his curtains, he also uses 2 cm of white fabric. Express the amount of white
defon

Answer:

The amount of white fabric to coloured fabric as a ratio is 20:11

Step-by-step explanation:

We are given that For each 11 mm of colored fabric Nick uses to make his curtains, he also uses 2 cm of white fabric.

Length of colored fabric = 11 mm

Length of White fabric = 2 cm

1 cm = 10 mm

2 cm = 20 mm

So, length of white fabric = 20 mm

So, Ratio of the amount of white fabric to coloured fabric = \frac{20}{11}

Hence the amount of white fabric to coloured fabric as a ratio is 20:11

3 0
3 years ago
The graph of a quadratic f(x) intersects the x-axis at –15 and 9. What is a possible
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the point that the function intercepts the x axis are the zeros of the function, where the products set equal to zero give you the x coordinate in which it intercepts.

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(x+15)(x-9)

or

x^2+6x-135

5 0
2 years ago
Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc
Rashid [163]

Answer:

The system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

h+s=15 \ \ \ \ equation \ 1

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

0.2h+0.1s=2 \ \ \ \ \ equation \ 2

Hence the system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3

Now Subtracting equation 1 from equation 3 we get;

(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5

Now Substituting the value of h in equation 1 we get;

h+s= 15\\5+s =15\\s=15-5\\s=10

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

5 0
3 years ago
Pls help!! Find the volume of the flower vase. Round to the nearest tenth.
Contact [7]

Answer:

Volume = 1596.2 cubic cm

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3 years ago
A caterpillar crawling in a straight line across a coordinate plane starts at point (-3,
Irina18 [472]

9514 1404 393

Answer:

  15

Step-by-step explanation:

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  p = (-3, -4) +t(28, 42)

  p = (-3, -4) +14t(2, 3)

where t takes on any value between 0 and 1.

If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.

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The caterpillar touches 15 points with integer coordinates.

7 0
2 years ago
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