Question

Hello! Guys I need some you to help me to solve this Areas of triangles homework. Shown down below. can you also give me the equation to solve it aswell.
I also need help on theses trapezium area questions can you give me the equation.
thanks!
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Answer 1

Answer:

sorry I didn't this answer

Answer 2

Answer:

see explanation

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

(1)

b = 6 and h = 9 , then

A = $\frac{1}{2}$ × 6 × 9 = 3 × 9 = 27 cm²

(2)

b = 3 and h = 5 , then

A = ×$\frac{1}{2}$ × 3 × 5 = 1.5 × 5 = 7.5 cm²

(3)

b = 6 and h = 10 , then

A = $\frac{1}{2}$ × 6 × 10 = 3 × 10 = 30 cm²

(4)

b = 8 and h = 14 , then

A = $\frac{1}{2}$ × 8 × 14 = 4 × 14 = 56 cm²

(5)

b = 7 and h = 9 , then

A = $\frac{1}{2}$ × 7 × 9 = 3.5 × 9 = 31.5 cm²

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The figures are composed of a rectangle and a triangle

The area is the sum of the areas of the rectangle and the triangle

A = (5 × 4) + $\frac{1}{2}$ × 5 × 4

   = 20 + 10

    = 30 cm²

(2)

A = (7 × 5) + $\frac{1}{2}$ × 7 × 2

   = 35 + 7

    = 42 cm²

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The area (A) of a trapezium is calculated as

A = $\frac{1}{2}$ h (a + b)

where h is the perpendicular height and a, b the parallel bases

(1)

A = $\frac{1}{2}$ × 5 × (7 + 11) = 2.5 × 18 = 45 cm²

(2)

A = $\frac{1}{2}$ × 6 × (6.6 + 8.4) = 3 × 15 = 45 cm²

(3)

A = $\frac{1}{2}$ × 4.3 × (9.1 + 7.1) = 2.15 × 16.2 = 34.83 cm²

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The figure consists of a rectangle in the middle and 2 trapezium at the ends

A = $\frac{1}{2}$ × 6 × (10 + 12) + (12 × 15) + $\frac{1}{2}$ × 11 × (12 + 9)

    = 3 × 22 + 180 + 5.5 × 21

     = 66 + 180 + 115.5

     = 361.5 m²

Divide by 20 to find number of cans required

361.5 ÷ 20 = 18.075

Only whole tins can be bought , so 19 tins required

cost = 19 × £6 = £114