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Hoochie [10]
3 years ago
12

Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be app

roximated by v(t) = 525,600(0.42t2 + 2.7t − 1) hours of video per year (0.5 ≤ t ≤ 7), where t is time in years since the start of 2005.† Use a definite integral to estimate the total number of hours of video uploaded from the start of 2006 to the start of 2011. (Round your answer to the nearest million hours of video.)
Mathematics
1 answer:
xeze [42]3 years ago
6 0
You have to solve this integral

\int\limits^7_{0.5} {525600(0.42 t^{2} +2.7t-1)} \, dt

That integral is easy to solve:

525600[0.42 t^3/3 + 2.7t^2/2 - t] eavluated between the limits of the integral, i.e. 7 and 0.5
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