Hcf and LCM of 391 and 236
1 answer:
You might be interested in
Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1
∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2
∴ y = 0.12
You can use the properties of logarithm to get to the solution.
The approximate value for given term is given by
When you raise a number with an exponent, there comes a result.
Lets say you get
Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows
Some properties of logarithm are:
Thus,
The approximate value for given term is given by
Learn more about logarithm here: