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3 years ago

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The table shows the low outside temperatures for Monday, Tuesday, and Wednesday. By how many degrees did the low temperature inc

rease from Monday to Tuesday? Addition and Subtraction Applications A. 5.6° B. 11.9° C. 17.5° D. 23.1°

1 answer:

sammy [17]3 years ago

5 0

You would subtract: -8.6-(-12.5) to get 3.9 increase

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17 = -47 + 6.98x. solve the equation. round your answer to the nearest hundredth

shutvik [7]

Solving it and nearing it to the hundredth would be 9.169 :)

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3 years ago

Read 2 more answers

For what value of k will the relation not be a function<br> R={(k-8.3+2.4k,-5),(3/4k,4)}

igomit [66]

Step-by-step explanation:

hope you can understand

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2 years ago

How do i graph 3tan(x+30)

Marina CMI [18]

$y = 3tan(x + 30)$
$y = 3(\frac{tan(x) + tan(30)}{1 - tan(x)tan(30)})$
$y = \frac{3(tan(x) + tan(30))}{1 - tan(x)tan(30)}$
$y = \frac{3(tan(x)) + 3(tan(30))}{1 - tan(x)tan(30)}$
$y = \frac{3tan(x) + 3tan(30)}{1 - tan(x)tan(30)}$

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3 years ago

Jaden use Tony Curtis to make a design above the stove 15 out of 20 of his tires were green what is an equivalent fraction for t

ratelena [41]

Answer:

3/4

Step-by-step explanation:

15/20 = 3/4

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3 years ago

What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?

bezimeni [28]

$3\equiv3\mod{20}$
$3^2\equiv9\mod{20}$
$3^3\equiv27\equiv7\mod{20}$
$3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}$

$7\equiv7\mod{20}$
$7^2\equiv49\equiv9\mod{20}$
$7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}$
$7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}$

$9\equiv9\mod{20}$
$9^2\equiv3^4\equiv1\mod{20}$

$11\equiv11\mod{20}$
$11^2\equiv121\equiv1\mod{20}$

$13\equiv-7\equiv13\mod{20}$
$13^2\equiv169\equiv9\mod{20}$
$13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}$
$13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}$

$17\equiv-3\equiv17\mod{20}$
$17^2\equiv(-3)^2\equiv9\mod{20}$
$17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}$
$17^4\equiv(-3)^4\equiv81\equiv1\mod{20}$

$19\equiv-1\equiv19\mod{20}$
$19^2\equiv19(-1)\equiv-19\equiv1\mod{20}$

Generally speaking, a number $x$ coprime to $n$ will be a primitive root of $n$ if we have $x^n\equiv x\mod{n}$ , or $x^{n-1}\equiv1\mod{n}$ . In other words, if $x$ is of order $n-1$ modulo $n$ , then $x$ is a primitive root of $n$ .

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.

6 0

4 years ago