<h2>
Greetings!</h2>
Answer:
3⋅(5⋅x)
5⋅(x⋅3)
15x
Step-by-step explanation:
As the values are inside the brackets, it does not matter what side the (x3) is on, so 3⋅(5⋅x) is equivalent.
Multiplying the contents of the brackets in the third one (x * 3) by 5 gives the same value as 3 * (x * 5) so 5⋅(x⋅3) is also equivalent.
On multiplying the brackets out:
5 * x = 5x
5x * 3 = 15x
So 15x is also equivalent.
<h2>Hope this helps!</h2>
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 330, \sigma = 12](https://tex.z-dn.net/?f=%5Cmu%20%3D%20330%2C%20%5Csigma%20%3D%2012)
a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![0.842 = \frac{X - 330}{12}](https://tex.z-dn.net/?f=0.842%20%3D%20%5Cfrac%7BX%20-%20330%7D%7B12%7D)
![X - 330 = 12*0.842](https://tex.z-dn.net/?f=X%20-%20330%20%3D%2012%2A0.842)
![X = 340.1](https://tex.z-dn.net/?f=X%20%3D%20340.1)
Weights of at least 340.1 are in the highest 20%.
It wouldn't let me post, so I screenshotted:
Answer:c
Step-by-step explanation:
c
Answer:
x = 2π3
Step-by-step explanation:
csc(x)csc(x) , x=πx=π
3x+2y+zx+y+z3x+2y+zx+y+z , x=2x=2 , y=3y=3 , z=1z=1
cot(3x)cot(3x) , x=2π3
Hope this helps :)