Question

A rectangle's length is 8 inches more than three times the width. If the perimeter is 128 inches, what are the rectangle's dimensions (length and width)

Answer 1

Length (L): 3w + 8

width (w): w

Perimeter (P) = 2L + 2w

               128 = 2(3w + 8) + 2(w)

               128 = 6w + 16 + 2w

               128 = 8w + 16

                 112 = 8w

                   14 = w

Length (L): 3w + 8   = 3(14) + 8   = 42 + 8   = 50

Answer: width = 14 inches, length = 50 inches