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2 years ago

Cuanto da (9+4m)² cuadrado de binomio ayudaaaaa

Mathematics

1 answer:

Korolek [52]2 years ago

8 0

Answer:

16m^2 + 72m + 81

Step-by-step explanation:

you expand it, by (9+4m)(9+4m), using distributive property you get

81 + 36m + 36m + 16m^2, simplifying you get the answer

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Triangle XYZ and EFG are given. ΔXYZ≅ΔEFG by SAS. If m∠EFG = 5p-2, YZ=2n-5 and GF=n+5 then which of the following statements are

VMariaS [17]

Answer:

A. ZY=15

Step-by-step explanation:

Insufficient information is given about angles to make any statement about the value of p or the measures of any angles. (Eliminates B,C,D,E)

Side YZ corresponds to side FG. Since they are congruent, their measures are the same. This means ...

2n -5 = n +5

n = 10 . . . . . . . . add 5-n

YZ = ZY = 2·10 -5 = 15 . . . . . . matches choice A

4 0

3 years ago

A search committee is formed to find a new software engineer.

Free_Kalibri [48]

Answer:

(a) 1,902,231,808,400

(b) 84

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\cdot(n-k)!}$

(a)

Compute the number of ways to select 9 applicants from 100 as follows:

${100\choose 9}=\frac{100!}{9!\cdot(100-9)!}$

$=\frac{100!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92\times 91!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92}{9!}\\\\=1902231808400$

(b)

Compute the number of ways to select 6 people from 9 as follows:

${9\choose 6}=\frac{9!}{6!\cdot(9-6)!}$

$=\frac{9!}{6!\times 3!}\\\\=\frac{9\times 8\times 7\times 6!}{6!\times 3!}\\\\=\frac{9\times 8\times 7}{3!}\\\\=84$

(c)

Compute the number of ways to select top 3 candidates from 6 as follows:

${6\choose 3}=\frac{6!}{3!\cdot(6-3)!}$

$=\frac{6!}{3!\times 3!}\\\\=\frac{6\times 5\times 4\times 3!}{3!\times 3!}\\\\=\frac{6\times 5\times 4}{3!}\\\\=20$

7 0

3 years ago

A survey of a group of seventh graders and a group of teachers at a local middle school asked how many siblings they each have.

erastovalidia [21]

Answer:

the same number of teachers as students were surveyed...im not exactly sure

Step-by-step explanation:

4 0

3 years ago

Let N be the number of data entries in a population and n be the number of data entries in a sample data set. Describe the diffe

Shkiper50 [21]

Answer:

Step-by-step explanation:

During the calculation of any population standard deviation, the sum of the squared deviation is usually divided by N, which is the number of data entry in the population. Thereafter, the square root of the result would be taken.

On the other hand, during the calculation of the sample standard deviation, the sum of the squared deviations is usually divided by n - 1, with n being number of entries in the sample data set. Thereafter, the square root of the result would be taken.

3 0

3 years ago

Which equation is shown in the graph?

Gekata [30.6K]

Hmmmm judging by the values in between integers, like 2.5, 1.5, -2.5, -3.5 and so on, those values always produce a smaller number hmm that sounds whack... lemme put it differently.

a floor() function, namely ⌊x⌋ like that, will floor the decimal values, so ⌊2.5⌋ floors to 2, because 2.5 is between 2 and 3, and the smallest is 2, the "floor", the 3 will be the "ceiling".

so for a floor function, ⌊1.5⌋ is 1, 1.5 is between 1 and 2, 1 is the smallest, ⌊-3.5⌋ is -4, recall that on the negative side, the closer to 0, the larger, so -1 is much larger than -1000.

and say ⌊-1.35⌋ is -2, -1.35 is between -2 an -1 and -2 is the smallest, the "floor".

that said

x = 2.5 ⌊ 2.5 + 3⌋ is ⌊5.5⌋ which is 5

x = 1.5 ⌊ 1.5 + 3 ⌋ is ⌊4.5⌋ which is 4

x = -2.749 ⌊ -2.749 + 3⌋ is ⌊0.251⌋ which is 0

anyway and so on, so you can pretty much see is the floor function of ⌊ x + 3⌋.

6 0

3 years ago