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kipiarov [429]
1 year ago
11

Cuanto da (9+4m)² cuadrado de binomio ayudaaaaa

Mathematics
1 answer:
Korolek [52]1 year ago
8 0

Answer:

16m^2 + 72m + 81

Step-by-step explanation:

you expand it, by (9+4m)(9+4m), using distributive property you get

81 + 36m + 36m + 16m^2, simplifying you get the answer

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4 0
3 years ago
The sum of three numbers is 11 . The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is
Assoli18 [71]

Answer:

4, 6, 1

Step-by-step explanation:

We can solve this problem using a system of equations:

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First, we can substitute the value of b from equation #3 into equation #1:

b = 4a - 10

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Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:

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4 0
2 years ago
Simplify the expression -2x^2(4x − 3).<br> -8x3 − 6x2<br> -8x3 + 6x2<br> 8x3 − 6x2<br> 8x3 + 6x2
Digiron [165]
To simplify the expression we are going to use the distributive property of multiplication: a(b+c)=ab+ac.
We can infer from our problem that a=-2x^2, b=4x, and c=-3. So lets apply the property to simplify our expression:
-2x^2(4x-3)=(-2x^2)(4x)+(-2x^2)(-3)
(-2x^2)(4x)+(-2x^2)(-3)=-8x^3+6x^2

We can conclude that the correct answer is <span>-8x3 + 6x2</span>
8 0
3 years ago
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