2(3a+8) I used photo math, and it gave me a step by step. The top steps are factor the expressions (20a+4)-(14a-12), which is (4(5a+1)-2(7a-6)
PLEASE HELP ASAP Given the right information, can you construct a function?
2 answers:
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Answer:
range of f(x) = [-4, -2) ∪ [2, 8)
a+b+c+d = -4
Step-by-step explanation:
The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.
The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.
The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.
Answer:
D(-2, 5).
Step-by-step explanation:
We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).
And we want to determine the coordinates of D.
Recall that the midpoint is given by:
Let C(10, -5) be (<em>x</em>₁<em>, y</em>₁) and Point D be (<em>x</em>₂<em>, y</em>₂). The midpoint M is (4, 0). Hence:
This yields two equations:
Solve for each:
And:
In conclusion, Point<em> </em>D = (-2, 5).