The length of one of the sides of the larger pentagon is 24 cm. The length of one of the sides of the smaller pentagon is 8 cm.
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So, if the larger pentagon is 3x the size of the smaller pentagon, we can find the area of the smaller pentagon by dividing the area of the larger pentagon by 3.
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The area of the smaller pentagon is 45in²
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Step-by-step explanation:
you need to substitute the x in (7x +2y=13) with (x=2y+11) to solve it
Answer:
y = 
Step-by-step explanation:
Given
x(y + 2) = 3x + y ← distribute parenthesis on left side
xy + 2x = 3x + y ( subtract 2x from both sides )
xy = x + y ( subtract y from both sides )
xy - y = x ← factor out y from each term on the left side )
y(x - 1) = x ← divide both sides by (x - 1)
y =
side = 8 m
the area of the rectangle = length × width = 16 × 4 = 64 m²
the area of the square = s² ( where s is the length of a side ), hence
s² = 64 ( since areas are equal )
take the square root of both sides
s = √64 = 8 m
