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andrezito [222]
2 years ago
13

At 6:00 a.m., the outside temperature was –14.4⁰. By noon, the outside temperature had dropped 8.1⁰. What was the outside temper

ature at noon? 6.3⁰ –6.3⁰ 22.5⁰ –22.5⁰
Mathematics
2 answers:
Advocard [28]2 years ago
5 0
-14.4 - 8.1 = - 22.5

The outside temperature at noon is - 22.5 degrees
iogann1982 [59]2 years ago
3 0
The answer is -22.5. All you do is subtract 8.1 from -14.4. It is really easy
 -14.4
-  8.1
---------
-22.5
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In parallelogram HJKL if HM=12 find HK.<br> K<br> M<br> M<br> H<br> L
Anestetic [448]

Answer:

HK = 24

Step-by-step explanation:

HK and JL are diagonals of the parallelogram.

Recall that diagonals of a parallelogram bisect each other. This implies that, they divide each other into equal parts.

Therefore,

HK = 2(HM)

HM = 12

Thus,

HK = 2(12)

HK = 24

7 0
2 years ago
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Ilia_Sergeevich [38]

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Step-by-step explanation:

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4 0
3 years ago
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garri49 [273]
We have that
<span>y=2x+4--------> equation 1
3x−6y=3-------> equation 2

step 1
</span>I substitute the value of y in equation 1 for the value of y in equation 2<span>
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step 2
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the answer is 
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y=-2



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3 years ago
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luda_lava [24]

Answer:

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Step-by-step explanation:

4 0
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