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erma4kov [3.2K]
3 years ago
10

A projectile is launched upward from a height of 704 feet with an initial velocity of 112 ft/s. The equation gives the height h

after t seconds. find the number of seconds until it returns to the ground
Mathematics
1 answer:
Feliz [49]3 years ago
4 0
We are given the data ho equal to 704 feet and vo equal to 112 feet per second. We apply then kinematics equation: h = ho + vot - 1/2 gt2. Substituting to the given equation, 
h = 704 + 112t - 1/2 * 32*t2when h is equal to zero,0 = 704 + 112t - 1/2 * 32*t2t is equal to 11 seconds
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Neporo4naja [7]

Answer:

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Step-by-step explanation:

Given the quadratic function

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f\left(x\right)=\:5x^2\:-\:4x\:+\:9

substitute x = 3

f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9

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