A projectile is launched upward from a height of 704 feet with an initial velocity of 112 ft/s. The equation gives the height h
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Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
<em><u>Recall:</u></em>
- A line that divides a segment into two equal parts is referred to as segment bisector.
In the diagram attached below, line n divides XY into XM and MY.
Thus, the segment bisector of XY is: line n.
<em><u>Find the value of x:</u></em>
XM = MY (congruent segments)
- Substitute
- Collect like terms and solve for x
XY = XM + MY
- Plug in the value of x
Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
Learn more here:
First, multiply the first equation by 3 to get:
Then, add the two equations together to get
We can follow that x=2. Plugging in x=2, we get that y=-4.
Therefore, the solution of (2,-4)