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jarptica [38.1K]
3 years ago
10

The Formula for the area of a trapezoid is A=1/2(b1+b2)h when this equation is solve for B1, One equation is b1=2A/h -b2 which o

f the following is an equivalent equation to find b1

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

  see below

Step-by-step explanation:

Multiply by 2 and expand the right side:

  2A = b1h +b2h

Subtract the b2 term:

  2A -b2h = b1h

Divide by h:

  b1 = (2A -b2h)/h

Contact [7]3 years ago
3 0

Answer:

A.  b1 = 2A-b2h/h

Step-by-step explanation:

Got it correct on edg2020

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Describe the graph of y = 3x2 and compare it with the graph of y=x^2.
professor190 [17]

Answer:

y=-x^2 is just y=x^2 reflected over the x-axis. In other words, the parabola is upside-down.

Step-by-step explanation:

8 0
3 years ago
Solve for x please help ! (show work)
Alina [70]

Answer:

x = -5

Step-by-step explanation:

-(5x-2) = 27

Distribute the minus sign

-5x +2 = 27

Subtract 2 from each side

-5x +2-2 = 27-2

-5x = 25

Divide by -5

-5x/-5 = 25/-5

x = -5

5 0
3 years ago
Read 2 more answers
Anya recorded the height in inches of 10 students in her class. The results are shown below.
Juliette [100K]
D, add all your answers than divide by how many numbers there are
8 0
3 years ago
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Someone please help me I’ll give out brainliest please dont answer if you don’t know
natta225 [31]

Answer:

12.5(x  + 20) = 460 \\ x + 20 = 460 \div 12.5 \\ x + 20 = 36.8 \\ x = 36.8 - 20 \\ x = 16.8

Hence, 16.8 miles is your answer

3 0
3 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
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