All you gotta do is pick a random point on the x-axis, lets say, x=2 in this case, and plug it into the equation.
If x=2, y = (1/2)2 - 3 = 2 - 3 = -1
When x = 2, y = -1
Now pick another point, x = 1
x = 1, y = (1/2)1 - 3 = 0.5 - 3 = - 2.5
When x = 1, y = - 2.5
Draw a cross on those 2 points, on the 2d plane
(1, -2.5) and (2, -1)
and draw a line between them, and make the line continue past the points, having no boundaries but the paper you hold, keeping it straight the entire time. With not turns.
If you want to draw out a table, make it have 2 rows, and 6 columns.
Write x in the first column of the first row, and write y in the first column of the second row.
Now, write down a different, random x value, in each column in the first row.
In the second row, in each column, write the y value, that corresponds to the x value given above each individual column, based on the equation
y = 1/2x - 3.
3x+5=2x-10
-2x -2x
X+5=-10
-5 -5
X=-15
3(-15)+y=5
-45+y=5
+45 +45
y=50
2(-15)-y=10
-30-y=10
+30 +30
-y=40
Divide by -1 on both sides
y=-40
x= 15
4x+8x: 180
12x: 180
x: 180/12
x: 15
pls give brainlist
have a great day :)
Answer:
We conclude that option A is true as x = 1 is the root of the polynomial.
Step-by-step explanation:
Given the polynomial
Let us determine the root of the polynomial shown below.
switch sides
as
so the equation becomes
Using the zero factor principle
solving
and
The possible roots of the polynomial will be:
Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.
Answer:
We print -> 21m + 25 ≤ 500
Print so good -> 18m + 44 ≤ 500
Maximum mats from We Print : the integer part of (500-25)/21 = 22
Maximum mats from Print So Good: the integer part of (500-45)/18 = 25
#Note
We take the integer part of the division because a mat cannot be in portions
Answered by GAUTHMATH
