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aliya0001 [1]
3 years ago
7

My linear expression y= 5x -3 What is an equivalent to this problem and is it equal​

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Answer:

5x+y=-3

Step-by-step explanation:

azamat3 years ago
3 0

Answer:

<h2>5x - y = 3</h2><h2>5x - y - 3 = 0</h2>

Step-by-step explanation:

y = 5x - 3   <em>it's a slope-intercept form</em>

<em />

y = 5x - 3         <em>subtract 5x from both sides</em>

-5x + y = -3          <em>change the signs</em>

5x - y = 3     <em>it's a standard form</em>

<em />

5x - y = 3          <em>subtract 3 from both sides</em>

5x - y - 3 = 0         <em>it's a general form</em>

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2 years ago
What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?
erica [24]

x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)

= -x^2 + 6xy + 8y^2

5 0
2 years ago
98464 rounded to the nearest ten thousand?​
dusya [7]

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100000

Step-by-step explanation:

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3 years ago
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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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