For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Answer:
here you go..............
Step-by-step explanation:
- To find the E(X) expected value, you come up with the different probabilities for each outcome
- your set of outcomes after 3 tosses would be = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} where H is heads and T is tails
- Each element has a probability of 1/8 so let x represent number of tails
- The E(x)=Summation (x times P(x))
- Now which probability is 1.5 tails? None, so it is either 2 tails or 1 tails
- So you can expect to lose money in 1 game
- But as you play more games the probability of getting 3 tails becomes more and more likely, so you can expect to win in a 100 games
Answer:
1 3/11
Step-by-step explanation:
The x-value of -7 shows up more than once in relation ...
B. X -7 -5 -7 2 Y 34 32 40 34
_____
When there is more than one y-value for an x-value, the relation is NOT a function.