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aliya0001 [1]
3 years ago
7

My linear expression y= 5x -3 What is an equivalent to this problem and is it equal​

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Answer:

5x+y=-3

Step-by-step explanation:

azamat3 years ago
3 0

Answer:

<h2>5x - y = 3</h2><h2>5x - y - 3 = 0</h2>

Step-by-step explanation:

y = 5x - 3   <em>it's a slope-intercept form</em>

<em />

y = 5x - 3         <em>subtract 5x from both sides</em>

-5x + y = -3          <em>change the signs</em>

5x - y = 3     <em>it's a standard form</em>

<em />

5x - y = 3          <em>subtract 3 from both sides</em>

5x - y - 3 = 0         <em>it's a general form</em>

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What are two things you will need to write an equation for a line?
vlabodo [156]

Answer:

Slope and y intercept.

Step-by-step explanation:

This is necassary to write the equation of a line in y=mx+b

m is where the slope goes, and b is the y intercept.

Alternatively, you could also write the equation for a line with a point on the line and the slope.

You would then write it in point slope formula:

y-y1=m(x-x1)

This can later be converted into slope intercept form.

3 0
4 years ago
What is the solution of ?<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20x-7%3D%5Cfrac%7B3%7D%7B4%7D%20x%2B14" id="Tex
Nonamiya [84]

Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

Find the common denominator.

\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x(-7)}{2}=\dfrac{3}{4}x+14   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3}{4}x+14   }

Combine the multiplied terms into a single fraction

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+14   }

Find the common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+\dfrac{4\cdot14}{4}    }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+56}{4}   }

Eliminate the denominators of the fractions.

\bf{4\cdot\dfrac{5x-14}{2}=4\cdot\dfrac{3x+56}{4}   }

Cancel the multiplied terms that are in the denominator.

\bf{2(5x-14)=3x+56}

To distribute.

\bf{10x-28=3x+56 }

Add 28 to both sides.

\bf{10x-28+28=3x+56+28 }

Simplify

\bf{10x=3x+84 }

Subtract 3x from both sides.

\bf{10x-3x=3x+84-3x }

Simplify

\bf{7x=84 }

Divide both sides by the same factor.

\bf{x=\dfrac{84}{7} }

Simplify

\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
  9. \bf{23=23}

Checked ✅

3 0
2 years ago
Help !!!!!! Need to know ASAP
madreJ [45]

Answer:

Multiply by 5

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anastassius [24]
True.

two angles would be complementary if the sum of their angle measures is 90 degrees.

60 degrees and 30 degrees make a complementary angle while 90 and 90 degrees make a supplementary angle.
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Match each statement to it’s corresponding reason. Drake the items on the left to the correct location on the right PLEASE AND T
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Answer:

Step-by-step explanation:

1) \angle AED and \angle BEC are vertical angles

2) \angle AED and \angle BEC are created by intersecting lines (definition of vertical angles)

3) \angle AED and \angle AEB form a linear pair, \angle AEB and \angle BEC form a linear pair

4)  \angle AED and \angle AEB are supplementary, \angle AEB and \angle BEC are supplementary

5) \angle AED \cong \angle BEC

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