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Mariana [72]
3 years ago
7

How do you round 23 to the nearest thousand?​

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

You cannot round 23 to the nearest thousand.

There are only TWO PLACE VALUES in 23: ones and tens.

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At θ = 90°, the equation must evaluate to zero. The only one that does that is the 1st choice ...
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Given PQRS and ZS = 40°, what is the measure of ZR?<br> S<br> R<br> 40°
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it is 140° Bc angle S and Z should add up to 180
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Need help on these. Don't answer if you don't know. I'm looking at YOU, bmdaniel1
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Step-by-step explanation:

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3 years ago
Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
3 years ago
The lcm of 165xy and 77x 3 y is _____. 1,155x 3y 11xy 12,705x 4y 2 105x 3y
trapecia [35]
The least common multiple (LCM) can be determined by factoring out the terms first,
                             165xy = (3)(11)(5)(x)(y)
                              77x³y = (7)(11)(x)(x)(x)(y)
Copy the factors writing off the repeated factors only once,
                        LCM = (3)(11)(5)(x)(y)(7)(x)(x)= 1155x³y
The answer is 1155x³y (first choice) 
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3 years ago
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