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laiz [17]
3 years ago
12

A play yard is 26 ft by 29 ft. A fence is to be built around the yard. How many feet of fencing will be needed? If fencing costs

$5.50 per foot, what will be the cost of the fence?
Mathematics
1 answer:
Radda [10]3 years ago
8 0
The total cost of the fence is $302.5
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Simplify: <br> <img src="https://tex.z-dn.net/?f=2%2F5%281%2F3x-15%2F8%29-1%2F3%281%2F2-2%2F3x%29" id="TexFormula1" title="2/5(1
expeople1 [14]

Answer:

16/45x-11/12

Step-by-step explanation:

2/5(1/3x-15/8)-1/3(1/2-2/3x)\\= 2/15x-30/40-1/6+2/9x\\= 16/45x-11/12

3 0
3 years ago
Read 2 more answers
8. An intrusion prevention system can either wait until it has all the information it needs or can allow packets through based o
MrRa [10]

<u>Explanation:</u>

<em>Remember, </em>any network security system that constantly monitors a network infrastructure in other to detect and prevent threats to the network is called an intrusion prevention system (IPS.

Many experts agree that a major advantage of waiting until the intrusion system <em>has all the information</em> it needs is that it would allow for easy sensing of a packet drop that can stop the trigger packet.

4 0
2 years ago
Think about your previous math courses. Identify one tope that you learned about which
saw5 [17]

The answer for this question I don’t think could be answered by anyone but yourself. To help you figure this out, just simply think about all of the math courses you’ve had previous to your current course and think about which course you did best in.

8 0
2 years ago
The price paid for a $4.50 pen after a 60% discount is applied​
Effectus [21]

Answer:

1.80

Step-by-step explanation:

trust me 100% sure

8 0
2 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
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