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elixir [45]
3 years ago
6

What is the greatest common factor of 142 and 148

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 142\ and\ 148\\can\ be\ divided\\\\
142:2\\
71:71\\\\
148:2\\
74:2\\
37:37\\\\GCF=2\\\\Greatest\ common\ factor\ of\ 142\ and\ 148\ is\ equal\ to\ 2.
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A sequence is defined by the explicit formula an=3n+4 Which recursive formula represents the same sequence of numbers?
fomenos

Answer:

Option (3)

Step-by-step explanation:

Explicit formula of the sequence is,

a_n=3^n+4

From this explicit formula,

First term of the sequence will be,

a_1=(3^1)+4

a_1=7

Second term of the sequence,

a_2=(3^2)+4

a_2 = 13

3rd term of the sequence,

a_{3}=(3^3)+4

   = 31

Sequence formed,

7, 13, 31 ..........

From the given options,

Recursive formula,

a_n=3a_{n-1}-8

a_2=3(a_1)-8

a_2=3(7)-8

a_2=21-8 = 13

a_3=3a_2-8

a_3=3a_2-8

a_3=3(13)-8

    = 39 - 8

    = 31

Sequence formed from this recursive formula will be,

7, 13, 31........

Therefore, Option (3) will be the answer.

5 0
3 years ago
Julie travels 3 times as fast as Bill. Traveling in opposite directions, they are 190 miles apart after 2.5 hours. Find their ra
Mkey [24]

Answer:

Step-by-step explanation:

Let b

Bill's rate of travel = x

Let Julie's rate of travel = 3x

The time each travels is 2.5 hours

Together they travel a distance of 190 miles

d = r*t

Bill's distance covered is r * t = 2.5x

Julie's distance travel is 2.5 * 3x = 7.5x

The total distance = Bill + Julie

2.5x + 7.5x = 190

10x = 190

x = 190/10

x = 19

Bill's distance = 2.5 * 19 = 47.5

Julie's distance = 19 * 7.5 = 142.5

Rate = distance / time

Bill's rate = 47.5 / 2.5 = 19 miles per hour.

Julie's rate = 142.5/2.5 = 57 miles per hour

Is there an easier way?

You should notice that Bill's rate is just x which is 19 miles / hour

You can also notice that Julie is going 3 times as fast or 19*3 = 57

6 0
3 years ago
Which system of equations represents the matrix shown below?
weqwewe [10]

Answer:

I don't know how to do it...

7 0
2 years ago
Read 2 more answers
1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the
zepelin [54]
1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2 

D.y=-x 

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6 

C.y=-3/2x+2  

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3 
 D.y=4 

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1 

B.y=-2x-1 

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3) 

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5 0
3 years ago
Does the point (4,2) satisfy y=5x
Arte-miy333 [17]
No. If you plug in the points, you have 2=5(4). 2=20 is not true, so it does not satisfy it

3 0
3 years ago
Read 2 more answers
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