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3 years ago

Write an expression to represent: Eight more than the product of two and a number number x

1 answer:

7 0

Eight more than the product of two and a number x

8+2x <== in mathematical form

Eight more= 8+

Product= multiply

number=x

~'Manda

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Ill give u brainly if u help on this one too please !

mrs_skeptik [129]

Answer:

The correct answer is B!

Step-by-step explanation:

I hope it helps you Sir (or ma'am.)

8 0

2 years ago

I need help once again.

muminat

The dimensions of the prism can be 2x, 2x+3 and x+6.

We first factor out the GCF of the trinomial. The GCF of the coefficients is 2. Each term has an x in common as well, so the GCF is 2x.

Factoring out the 2x, we have
2x(2x²+15x+18).

To factor the remaining trinomial, we find factors of 2*18=36 that sum to 15. 12*3 = 36 and 12+3 = 15. We split up 15x into 12x and 3x:

2x(2x²+12x+3x+18)

Now we group together the first two terms in parentheses and the last two:
2x((2x²+12x)+(3x+18))

Factor out the GCF of the first group:
2x(2x(x+6)+(3x+18))

Factor out the GCF of the second group:
2x(2x(x+6)+3(x+6))

Factoring out what these have in common,
2x(x+6)(2x+3)

8 0

2 years ago

Plot the points (0,1), (-1,3), (2, -3) and describe the resulting graph.

ivanzaharov [21]

check the picture below.

6 0

2 years ago

Pls help I need this RN

erica [24]

Answer:

3.2 , Edgar , Liam

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the <u>distance formula</u>.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$

$d =\sqrt{5^{2}+4^{2}}$

$d =\sqrt{25 + 16}$

$d =\sqrt{41}$ This is equal to approximately 6.40 units.

The last step is to find the perimeter. To find the perimeter, add of the three sides of the triangle together.

P = 5 units + 4 units + 6.4 units

P = 15.4 units

Therefore, the perimeter of this triangle is choice A, 15.4.

6 0

3 years ago