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laila [671]
3 years ago
6

3x-4=4x-10=90. Solve for x​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

the answer is 8

Step-by-step explanation:

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Please help i need to turn this in at 11:59 PM
vekshin1

Answer:

See explanation.

Step-by-step explanation:

To find the area of a parallogram, do A=Bh where a is the area, b is the base, and h is the height.

In this case, b is 9 cm while h is 6 cm. Do A=Bh by multiplying 9 cm by 6 cm. This will give us 54 cm².

The measurement we didn't use is the measure of the diagonal parts of the quadrilateral which, in this case, was 7.5 cm.

4 0
2 years ago
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I need to find length of MK​
Norma-Jean [14]

Answer:

Use the cosine rule

Step-by-step explanation:

1. Apply formula of c^2 = a^2 + b^2 - 2abcosC

2. Substitute known values in: c^2 = 36 + 4900 - 840cos120

3. Apply algebra and use the calculator

4. Final answer is 73.18 (2 decimal places)

7 0
3 years ago
Find the value of x if C is the midpoint of AB and AC = 5x and BC = 10
MrMuchimi

Answer:

x = 2

Step-by-step explanation:

AC = BC

5x = 10

x = 2

8 0
4 years ago
Brainliest giving to who gets this CORRECT first. Check all that apply.
lozanna [386]

Answer:

D.

Step-by-step explanation:

a² -b²= (a-b)(a+b)

100x²-49y²= (10x-7y)(10x+7y)

3 0
3 years ago
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Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give
LenaWriter [7]

Answer:

Equation of tangent will be y=\frac{x}{e}

Step-by-step explanation:

We have given the function y=x^2e^{-x}

We have to find the equation of tangent at the point (1,\frac{1}{e})

Equation of tangent is equal to \frac{dy}{dx}

So \frac{dy}{dx}=x^2\frac{d}{dx}e^{-x}+e^{-x}\frac{d}{dx}2x=-x^2e^{-x}+2e^{-x}

Now we have given point (1,\frac{1}{e})

So putting these points in the equation of tangent

\frac{dy}{dx}=-1^2e^{-1}+2e^{-1}

\frac{dy}{dx}=\frac{1}{e}

Now equation of tangent passing through (1,\frac{1}{e})

y-\frac{1}{e}=\frac{1}{e}(x-1)

y=\frac{x}{e}-\frac{1}{e}+\frac{1}{e}=\frac{x}{e}

4 0
3 years ago
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