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den301095 [7]
3 years ago
10

packs of pickled peppers were reduced to 20% off their original price of $3.50. Today there’s an additional 10% off the reduced

price. Find the new price for packs of pickled peppers.
Mathematics
2 answers:
IrinaVladis [17]3 years ago
6 0

Answer:

2.52


Step-by-step explanation:


sladkih [1.3K]3 years ago
3 0
20% of 3.50 = .7 3.50 - .7 = 2.8     10% of 2.80 = .28   2.80 - .28 = 2.52
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Plzzzzzz helpppppp!!!!!!
stepladder [879]

Answer:

h(x) ≤ 5

Step-by-step explanation:

The function and boundaries given are;

h(x) = x + 2, x < 3

And ;

h(x) = -x + 8, x ≥ 3

Now,in the first condition, the maximum value of x will be 2. This means the maximum value of h(x) there is;

h(2) = 2 + 2 = 4

For the second condition, x ≥ 3. Thus, the maximum value of x is 3.

This means that the maximum value of h(x) here is;

h(3) = -3 + 8 = 5

Foe the 2 conditions combined it is clear that the maximum value of h(x) is 5.

Thus,we can say; h(x) ≤ 5

3 0
3 years ago
HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). \frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}

2). \frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}

=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

3). \frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}

=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

=\frac{3x(x-5)}{x^{2}-7x+10}

=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}

4). \frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}

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=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}

5). \frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}

=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
3 years ago
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Rationalise the denominator of: -7/(√11 - √5)​
tatuchka [14]
-7(sqrt(11)+sqrt(5))/6


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Step-by-step explanation:


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Another way to write this is 3(4+7)
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