e EDF= Measure of angle DFG
Answer:
b.22.
Step-by-step explanation:
We are given that quadrilateral DEFG is a rectangle.
We know that every angle of reactangle is of 90 degrees.
We are given that
Measure of angle EDF=5x-3
Measure of angle DFG=3x+7
We know that every every angle of rectangle is equal.
Measure of angle EDF=Measure of angle DFG
![5x-3=3x+7](https://tex.z-dn.net/?f=5x-3%3D3x%2B7)
![5x-3x-3=7](https://tex.z-dn.net/?f=5x-3x-3%3D7)
By using subtraction property of equality
![2x-3=7](https://tex.z-dn.net/?f=2x-3%3D7)
By simplification
![2x=7+3](https://tex.z-dn.net/?f=2x%3D7%2B3)
By using subtarction property of equality
![2x=10](https://tex.z-dn.net/?f=2x%3D10)
![x=\frac{10}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B10%7D%7B2%7D)
By using division property of equality
![x=5](https://tex.z-dn.net/?f=x%3D5)
By simplification
Substitute the value x=5 then
Measure of angle EDF= ![5\times 5-3](https://tex.z-dn.net/?f=5%5Ctimes%205-3)
Measure of angle EDF=25-3
By simplification
Measure of angle EDF=22
Hence, the measure of angle EDF=
.