There is no choice on your list that must represent an odd integer.
If 'z' is an even integer, then (z-1) and (z+1) must both be odd integers.
A measurement that closely agrees with an accepted value is best described as a numerical
Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer:
A. 6^2/7 and (√6)^7
Step-by-step explanation:
Because we can't get 6 out of root as a whole we need to use the power to show its value when we do so.
The power of (√6)^7 has is seven and degree of the root is 2 so we have to put 2/7 over 6 when we take it out of root.
